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123112140000 = 253543316199
BaseRepresentation
bin111001010101000001…
…1100010110011100000
3102202202220012200222220
41302222003202303200
54004113201440000
6132320144231040
711615555631603
oct1625203426340
9382686180886
10123112140000
1148236658a53
121ba3a00b480
13b7bcba3025
145d5c7c033a
1533082eb1a0
hex1caa0e2ce0

123112140000 has 240 divisors, whose sum is σ = 405117820800. Its totient is φ = 32725440000.

The previous prime is 123112139993. The next prime is 123112140007. The reversal of 123112140000 is 41211321.

It is an interprime number because it is at equal distance from previous prime (123112139993) and next prime (123112140007).

It is a tau number, because it is divible by the number of its divisors (240).

It is a Harshad number since it is a multiple of its sum of digits (15).

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (123112140007) by changing a digit.

It is a polite number, since it can be written in 39 ways as a sum of consecutive naturals, for example, 19856901 + ... + 19863099.

It is an arithmetic number, because the mean of its divisors is an integer number (1687990920).

Almost surely, 2123112140000 is an apocalyptic number.

123112140000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 123112140000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (202558910400).

123112140000 is an abundant number, since it is smaller than the sum of its proper divisors (282005680800).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

123112140000 is an equidigital number, since it uses as much as digits as its factorization.

123112140000 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 6563 (or 6540 counting only the distinct ones).

The product of its (nonzero) digits is 48, while the sum is 15.

Adding to 123112140000 its reverse (41211321), we get a palindrome (123153351321).

The spelling of 123112140000 in words is "one hundred twenty-three billion, one hundred twelve million, one hundred forty thousand".