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123113030103020 = 22511443537940357
BaseRepresentation
bin11011111111100001111100…
…011011010010111111101100
3121010220111020202010110200102
4123333201330123102333230
5112114040441201244040
61113501202323450232
734634423440362266
oct3377417433227754
9533814222113612
10123113030103020
1136255a40a41271
1211984168826978
13539068014ab29
1422589b974ab36
15e376bbed0515
hex6ff87c6d2fec

123113030103020 has 24 divisors (see below), whose sum is σ = 258559957191984. Its totient is φ = 49240908426816.

The previous prime is 123113030102977. The next prime is 123113030103031. The reversal of 123113030103020 is 20301030311321.

It is a super-2 number, since 2×1231130301030202 (a number of 29 digits) contains 22 as substring.

It is a Harshad number since it is a multiple of its sum of digits (20).

It is a junction number, because it is equal to n+sod(n) for n = 123113030102983 and 123113030103001.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (31) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 268741319 + ... + 269199038.

It is an arithmetic number, because the mean of its divisors is an integer number (10773331549666).

Almost surely, 2123113030103020 is an apocalyptic number.

123113030103020 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

123113030103020 is an abundant number, since it is smaller than the sum of its proper divisors (135446927088964).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

123113030103020 is a wasteful number, since it uses less digits than its factorization.

123113030103020 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 537951809 (or 537951807 counting only the distinct ones).

The product of its (nonzero) digits is 324, while the sum is 20.

Adding to 123113030103020 its reverse (20301030311321), we get a palindrome (143414060414341).

The spelling of 123113030103020 in words is "one hundred twenty-three trillion, one hundred thirteen billion, thirty million, one hundred three thousand, twenty".

Divisors: 1 2 4 5 10 20 11443 22886 45772 57215 114430 228860 537940357 1075880714 2151761428 2689701785 5379403570 10758807140 6155651505151 12311303010302 24622606020604 30778257525755 61556515051510 123113030103020