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123113130031 is a prime number
BaseRepresentation
bin111001010101000011…
…1010100100000101111
3102202202222002000001201
41302222013110200233
54004113430130111
6132320221350331
711615600224153
oct1625207244057
9382688060051
10123113130031
1148237174861
121ba3a4083a7
13b7c015b848
145d5c99b063
1533084446c1
hex1caa1d482f

123113130031 has 2 divisors, whose sum is σ = 123113130032. Its totient is φ = 123113130030.

The previous prime is 123113130017. The next prime is 123113130043. The reversal of 123113130031 is 130031311321.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 123113130031 - 211 = 123113127983 is a prime.

It is a super-2 number, since 2×1231131300312 (a number of 23 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 123113129990 and 123113130008.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (123113137031) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 61556565015 + 61556565016.

It is an arithmetic number, because the mean of its divisors is an integer number (61556565016).

Almost surely, 2123113130031 is an apocalyptic number.

123113130031 is a deficient number, since it is larger than the sum of its proper divisors (1).

123113130031 is an equidigital number, since it uses as much as digits as its factorization.

123113130031 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 162, while the sum is 19.

Adding to 123113130031 its reverse (130031311321), we get a palindrome (253144441352).

The spelling of 123113130031 in words is "one hundred twenty-three billion, one hundred thirteen million, one hundred thirty thousand, thirty-one".