Base | Representation |
---|---|
bin | 111001010101000011… |
… | …1010100100000101111 |
3 | 102202202222002000001201 |
4 | 1302222013110200233 |
5 | 4004113430130111 |
6 | 132320221350331 |
7 | 11615600224153 |
oct | 1625207244057 |
9 | 382688060051 |
10 | 123113130031 |
11 | 48237174861 |
12 | 1ba3a4083a7 |
13 | b7c015b848 |
14 | 5d5c99b063 |
15 | 33084446c1 |
hex | 1caa1d482f |
123113130031 has 2 divisors, whose sum is σ = 123113130032. Its totient is φ = 123113130030.
The previous prime is 123113130017. The next prime is 123113130043. The reversal of 123113130031 is 130031311321.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 123113130031 - 211 = 123113127983 is a prime.
It is a super-2 number, since 2×1231131300312 (a number of 23 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 123113129990 and 123113130008.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (123113137031) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 61556565015 + 61556565016.
It is an arithmetic number, because the mean of its divisors is an integer number (61556565016).
Almost surely, 2123113130031 is an apocalyptic number.
123113130031 is a deficient number, since it is larger than the sum of its proper divisors (1).
123113130031 is an equidigital number, since it uses as much as digits as its factorization.
123113130031 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 162, while the sum is 19.
Adding to 123113130031 its reverse (130031311321), we get a palindrome (253144441352).
The spelling of 123113130031 in words is "one hundred twenty-three billion, one hundred thirteen million, one hundred thirty thousand, thirty-one".
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