Base | Representation |
---|---|
bin | 1011001100100111010100… |
… | …0011100101001000100111 |
3 | 1121120221201110111002110011 |
4 | 2303021311003211020213 |
5 | 3103202111034040033 |
6 | 42103430201511051 |
7 | 2410315325402566 |
oct | 263116503451047 |
9 | 47527643432404 |
10 | 12311340143143 |
11 | 3a17234611528 |
12 | 146a02aaa2487 |
13 | 6b3c53a5a662 |
14 | 307c2cc53bdd |
15 | 1653a5e5bccd |
hex | b32750e5227 |
12311340143143 has 2 divisors, whose sum is σ = 12311340143144. Its totient is φ = 12311340143142.
The previous prime is 12311340143111. The next prime is 12311340143173. The reversal of 12311340143143 is 34134104311321.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 12311340143143 - 25 = 12311340143111 is a prime.
It is a super-2 number, since 2×123113401431432 (a number of 27 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (12311340143173) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6155670071571 + 6155670071572.
It is an arithmetic number, because the mean of its divisors is an integer number (6155670071572).
Almost surely, 212311340143143 is an apocalyptic number.
12311340143143 is a deficient number, since it is larger than the sum of its proper divisors (1).
12311340143143 is an equidigital number, since it uses as much as digits as its factorization.
12311340143143 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 10368, while the sum is 31.
Adding to 12311340143143 its reverse (34134104311321), we get a palindrome (46445444454464).
The spelling of 12311340143143 in words is "twelve trillion, three hundred eleven billion, three hundred forty million, one hundred forty-three thousand, one hundred forty-three".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.074 sec. • engine limits •