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12311340143143 is a prime number
BaseRepresentation
bin1011001100100111010100…
…0011100101001000100111
31121120221201110111002110011
42303021311003211020213
53103202111034040033
642103430201511051
72410315325402566
oct263116503451047
947527643432404
1012311340143143
113a17234611528
12146a02aaa2487
136b3c53a5a662
14307c2cc53bdd
151653a5e5bccd
hexb32750e5227

12311340143143 has 2 divisors, whose sum is σ = 12311340143144. Its totient is φ = 12311340143142.

The previous prime is 12311340143111. The next prime is 12311340143173. The reversal of 12311340143143 is 34134104311321.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 12311340143143 - 25 = 12311340143111 is a prime.

It is a super-2 number, since 2×123113401431432 (a number of 27 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (12311340143173) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6155670071571 + 6155670071572.

It is an arithmetic number, because the mean of its divisors is an integer number (6155670071572).

Almost surely, 212311340143143 is an apocalyptic number.

12311340143143 is a deficient number, since it is larger than the sum of its proper divisors (1).

12311340143143 is an equidigital number, since it uses as much as digits as its factorization.

12311340143143 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 10368, while the sum is 31.

Adding to 12311340143143 its reverse (34134104311321), we get a palindrome (46445444454464).

The spelling of 12311340143143 in words is "twelve trillion, three hundred eleven billion, three hundred forty million, one hundred forty-three thousand, one hundred forty-three".