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123114013657 is a prime number
BaseRepresentation
bin111001010101000101…
…0101100001111011001
3102202210000201220011121
41302222022230033121
54004114141414112
6132320252325241
711615610564265
oct1625212541731
9382700656147
10123114013657
1148237718728
121ba3a773821
13b7c03aaabb
145d5cb4b0a5
15330856b407
hex1caa2ac3d9

123114013657 has 2 divisors, whose sum is σ = 123114013658. Its totient is φ = 123114013656.

The previous prime is 123114013643. The next prime is 123114013667. The reversal of 123114013657 is 756310411321.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 71393702416 + 51720311241 = 267196^2 + 227421^2 .

It is an emirp because it is prime and its reverse (756310411321) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 123114013657 - 211 = 123114011609 is a prime.

It is not a weakly prime, because it can be changed into another prime (123114013667) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 61557006828 + 61557006829.

It is an arithmetic number, because the mean of its divisors is an integer number (61557006829).

Almost surely, 2123114013657 is an apocalyptic number.

It is an amenable number.

123114013657 is a deficient number, since it is larger than the sum of its proper divisors (1).

123114013657 is an equidigital number, since it uses as much as digits as its factorization.

123114013657 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 15120, while the sum is 34.

Adding to 123114013657 its reverse (756310411321), we get a palindrome (879424424978).

The spelling of 123114013657 in words is "one hundred twenty-three billion, one hundred fourteen million, thirteen thousand, six hundred fifty-seven".