Base | Representation |
---|---|
bin | 1011001100100111100110… |
… | …0010110111000110100111 |
3 | 1121120221220201012011212201 |
4 | 2303021321202313012213 |
5 | 3103202234323431241 |
6 | 42103441451555331 |
7 | 2410320231460261 |
oct | 263117142670647 |
9 | 47527821164781 |
10 | 12311415452071 |
11 | 3a1727307920a |
12 | 146a05015bb47 |
13 | 6b3c66537758 |
14 | 307c38c58b31 |
15 | 1653ac885931 |
hex | b32798b71a7 |
12311415452071 has 2 divisors, whose sum is σ = 12311415452072. Its totient is φ = 12311415452070.
The previous prime is 12311415452059. The next prime is 12311415452173. The reversal of 12311415452071 is 17025451411321.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 12311415452071 - 211 = 12311415450023 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 12311415452071.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (12311415450071) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6155707726035 + 6155707726036.
It is an arithmetic number, because the mean of its divisors is an integer number (6155707726036).
Almost surely, 212311415452071 is an apocalyptic number.
12311415452071 is a deficient number, since it is larger than the sum of its proper divisors (1).
12311415452071 is an equidigital number, since it uses as much as digits as its factorization.
12311415452071 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 33600, while the sum is 37.
Adding to 12311415452071 its reverse (17025451411321), we get a palindrome (29336866863392).
The spelling of 12311415452071 in words is "twelve trillion, three hundred eleven billion, four hundred fifteen million, four hundred fifty-two thousand, seventy-one".
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