Base | Representation |
---|---|
bin | 1011001100101010100110… |
… | …0000011011100011010111 |
3 | 1121121000222210022121112212 |
4 | 2303022221200123203113 |
5 | 3103210411322340203 |
6 | 42104053354504035 |
7 | 2410346202161564 |
oct | 263125140334327 |
9 | 47530883277485 |
10 | 12312220121303 |
11 | 3a17646309103 |
12 | 146a23573501b |
13 | 6b40641639ab |
14 | 307cb3a7b86b |
15 | 1654083311d8 |
hex | b32a981b8d7 |
12312220121303 has 2 divisors, whose sum is σ = 12312220121304. Its totient is φ = 12312220121302.
The previous prime is 12312220121287. The next prime is 12312220121363. The reversal of 12312220121303 is 30312102221321.
12312220121303 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 12312220121303 - 24 = 12312220121287 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (12312220121363) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6156110060651 + 6156110060652.
It is an arithmetic number, because the mean of its divisors is an integer number (6156110060652).
Almost surely, 212312220121303 is an apocalyptic number.
12312220121303 is a deficient number, since it is larger than the sum of its proper divisors (1).
12312220121303 is an equidigital number, since it uses as much as digits as its factorization.
12312220121303 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 864, while the sum is 23.
Adding to 12312220121303 its reverse (30312102221321), we get a palindrome (42624322342624).
The spelling of 12312220121303 in words is "twelve trillion, three hundred twelve billion, two hundred twenty million, one hundred twenty-one thousand, three hundred three".
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