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123122220131041 is a prime number
BaseRepresentation
bin11011111111101010100000…
…001100011110001011100001
3121010221100222012210021010121
4123333222200030132023201
5112114213301323143131
61113505322254000241
734635200251336015
oct3377524014361341
9533840865707117
10123122220131041
113625992752434a
1211985ab24a6081
1353914b60a3531
14225920c0aa545
15e37a58be6911
hex6ffaa031e2e1

123122220131041 has 2 divisors, whose sum is σ = 123122220131042. Its totient is φ = 123122220131040.

The previous prime is 123122220130991. The next prime is 123122220131081. The reversal of 123122220131041 is 140131022221321.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 85580926992016 + 37541293139025 = 9250996^2 + 6127095^2 .

It is a cyclic number.

It is not a de Polignac number, because 123122220131041 - 29 = 123122220130529 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 123122220130997 and 123122220131015.

It is not a weakly prime, because it can be changed into another prime (123122220131081) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 61561110065520 + 61561110065521.

It is an arithmetic number, because the mean of its divisors is an integer number (61561110065521).

Almost surely, 2123122220131041 is an apocalyptic number.

It is an amenable number.

123122220131041 is a deficient number, since it is larger than the sum of its proper divisors (1).

123122220131041 is an equidigital number, since it uses as much as digits as its factorization.

123122220131041 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1152, while the sum is 25.

Adding to 123122220131041 its reverse (140131022221321), we get a palindrome (263253242352362).

The spelling of 123122220131041 in words is "one hundred twenty-three trillion, one hundred twenty-two billion, two hundred twenty million, one hundred thirty-one thousand, forty-one".