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12313012001209 is a prime number
BaseRepresentation
bin1011001100101101100010…
…1101001101100110111001
31121121010000222101021120021
42303023120231031212321
53103214022033014314
642104304123330441
72410404626065423
oct263133055154671
947533028337507
1012313012001209
113a17a12303207
12146a416980a21
136b415c23289a
14307d4acd1813
15165452b02324
hexb32d8b4d9b9

12313012001209 has 2 divisors, whose sum is σ = 12313012001210. Its totient is φ = 12313012001208.

The previous prime is 12313012001179. The next prime is 12313012001261. The reversal of 12313012001209 is 90210021031321.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 9265613338809 + 3047398662400 = 3043947^2 + 1745680^2 .

It is a cyclic number.

It is not a de Polignac number, because 12313012001209 - 211 = 12313011999161 is a prime.

It is a super-2 number, since 2×123130120012092 (a number of 27 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (12313012001509) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6156506000604 + 6156506000605.

It is an arithmetic number, because the mean of its divisors is an integer number (6156506000605).

Almost surely, 212313012001209 is an apocalyptic number.

It is an amenable number.

12313012001209 is a deficient number, since it is larger than the sum of its proper divisors (1).

12313012001209 is an equidigital number, since it uses as much as digits as its factorization.

12313012001209 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 648, while the sum is 25.

The spelling of 12313012001209 in words is "twelve trillion, three hundred thirteen billion, twelve million, one thousand, two hundred nine".