Base | Representation |
---|---|
bin | 1011001100101101100011… |
… | …0001000110011110111011 |
3 | 1121121010001001022001220121 |
4 | 2303023120301012132323 |
5 | 3103214022313124403 |
6 | 42104304201234111 |
7 | 2410404640542421 |
oct | 263133061063673 |
9 | 47533031261817 |
10 | 12313013020603 |
11 | 3a17a1293a089 |
12 | 146a417192937 |
13 | 6b415c4cb889 |
14 | 307d4b0b9111 |
15 | 165452c543bd |
hex | b32d8c467bb |
12313013020603 has 2 divisors, whose sum is σ = 12313013020604. Its totient is φ = 12313013020602.
The previous prime is 12313013020591. The next prime is 12313013020631. The reversal of 12313013020603 is 30602031031321.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-12313013020603 is a prime.
It is a super-2 number, since 2×123130130206032 (a number of 27 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (12313013020643) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6156506510301 + 6156506510302.
It is an arithmetic number, because the mean of its divisors is an integer number (6156506510302).
Almost surely, 212313013020603 is an apocalyptic number.
12313013020603 is a deficient number, since it is larger than the sum of its proper divisors (1).
12313013020603 is an equidigital number, since it uses as much as digits as its factorization.
12313013020603 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1944, while the sum is 25.
Adding to 12313013020603 its reverse (30602031031321), we get a palindrome (42915044051924).
The spelling of 12313013020603 in words is "twelve trillion, three hundred thirteen billion, thirteen million, twenty thousand, six hundred three".
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