Search a number
-
+
12313013102077 is a prime number
BaseRepresentation
bin1011001100101101100011…
…0001011010010111111101
31121121010001001110012200011
42303023120301122113331
53103214022323231302
642104304203103221
72410404641332102
oct263133061322775
947533031405604
1012313013102077
113a17a12995316
12146a417211b11
136b415c52999c
14307d4b0daaa9
15165452c6d5d7
hexb32d8c5a5fd

12313013102077 has 2 divisors, whose sum is σ = 12313013102078. Its totient is φ = 12313013102076.

The previous prime is 12313013102029. The next prime is 12313013102123. The reversal of 12313013102077 is 77020131031321.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 7799793281721 + 4513219820356 = 2792811^2 + 2124434^2 .

It is a cyclic number.

It is not a de Polignac number, because 12313013102077 - 215 = 12313013069309 is a prime.

It is a super-2 number, since 2×123130131020772 (a number of 27 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (12313013100077) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6156506551038 + 6156506551039.

It is an arithmetic number, because the mean of its divisors is an integer number (6156506551039).

Almost surely, 212313013102077 is an apocalyptic number.

It is an amenable number.

12313013102077 is a deficient number, since it is larger than the sum of its proper divisors (1).

12313013102077 is an equidigital number, since it uses as much as digits as its factorization.

12313013102077 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 5292, while the sum is 31.

Adding to 12313013102077 its reverse (77020131031321), we get a palindrome (89333144133398).

The spelling of 12313013102077 in words is "twelve trillion, three hundred thirteen billion, thirteen million, one hundred two thousand, seventy-seven".