Base | Representation |
---|---|
bin | 111001010101100100… |
… | …0011100010010001111 |
3 | 102202211011012022100101 |
4 | 1302223020130102033 |
5 | 4004132312414411 |
6 | 132322031311531 |
7 | 11616165304342 |
oct | 1625310342217 |
9 | 382734168311 |
10 | 123130201231 |
11 | 48245874694 |
12 | 1ba4407b5a7 |
13 | b7c3857b4b |
14 | 5d60d62459 |
15 | 3309bb78c1 |
hex | 1cab21c48f |
123130201231 has 2 divisors, whose sum is σ = 123130201232. Its totient is φ = 123130201230.
The previous prime is 123130201213. The next prime is 123130201237. The reversal of 123130201231 is 132102031321.
Together with previous prime (123130201213) it forms an Ormiston pair, because they use the same digits, order apart.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 123130201231 - 217 = 123130070159 is a prime.
It is a super-2 number, since 2×1231302012312 (a number of 23 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 123130201199 and 123130201208.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (123130201237) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 61565100615 + 61565100616.
It is an arithmetic number, because the mean of its divisors is an integer number (61565100616).
Almost surely, 2123130201231 is an apocalyptic number.
123130201231 is a deficient number, since it is larger than the sum of its proper divisors (1).
123130201231 is an equidigital number, since it uses as much as digits as its factorization.
123130201231 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 216, while the sum is 19.
Adding to 123130201231 its reverse (132102031321), we get a palindrome (255232232552).
The spelling of 123130201231 in words is "one hundred twenty-three billion, one hundred thirty million, two hundred one thousand, two hundred thirty-one".
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