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1231310013301 is a prime number
BaseRepresentation
bin10001111010101111110…
…010111100001101110101
311100201020010000120202201
4101322233302330031311
5130133210330411201
62341353410504501
7154650003265444
oct21725762741565
94321203016681
101231310013301
11435217447545
1217a777295131
138c15c1b26b4
144384a93cd5b
1522068831801
hex11eafcbc375

1231310013301 has 2 divisors, whose sum is σ = 1231310013302. Its totient is φ = 1231310013300.

The previous prime is 1231310013203. The next prime is 1231310013317. The reversal of 1231310013301 is 1033100131321.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1092706446276 + 138603567025 = 1045326^2 + 372295^2 .

It is an emirp because it is prime and its reverse (1033100131321) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1231310013301 - 237 = 1093871059829 is a prime.

It is a super-2 number, since 2×12313100133012 (a number of 25 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1231310019301) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 615655006650 + 615655006651.

It is an arithmetic number, because the mean of its divisors is an integer number (615655006651).

Almost surely, 21231310013301 is an apocalyptic number.

It is an amenable number.

1231310013301 is a deficient number, since it is larger than the sum of its proper divisors (1).

1231310013301 is an equidigital number, since it uses as much as digits as its factorization.

1231310013301 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 162, while the sum is 19.

Adding to 1231310013301 its reverse (1033100131321), we get a palindrome (2264410144622).

The spelling of 1231310013301 in words is "one trillion, two hundred thirty-one billion, three hundred ten million, thirteen thousand, three hundred one".