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12313101011311 is a prime number
BaseRepresentation
bin1011001100101101111000…
…0000110000100101101111
31121121010021011212110110201
42303023132000300211233
53103214212324330221
642104321023214331
72410410056466202
oct263133600604557
947533234773421
1012313101011311
113a17a58578881
12146a4407473a7
136b41747c9099
14307d58a61939
1516545a835891
hexb32de03096f

12313101011311 has 2 divisors, whose sum is σ = 12313101011312. Its totient is φ = 12313101011310.

The previous prime is 12313101011273. The next prime is 12313101011353. The reversal of 12313101011311 is 11311010131321.

12313101011311 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It is an emirp because it is prime and its reverse (11311010131321) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 12313101011311 - 211 = 12313101009263 is a prime.

It is a super-2 number, since 2×123131010113112 (a number of 27 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (12313101011011) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6156550505655 + 6156550505656.

It is an arithmetic number, because the mean of its divisors is an integer number (6156550505656).

Almost surely, 212313101011311 is an apocalyptic number.

12313101011311 is a deficient number, since it is larger than the sum of its proper divisors (1).

12313101011311 is an equidigital number, since it uses as much as digits as its factorization.

12313101011311 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 54, while the sum is 19.

Adding to 12313101011311 its reverse (11311010131321), we get a palindrome (23624111142632).

The spelling of 12313101011311 in words is "twelve trillion, three hundred thirteen billion, one hundred one million, eleven thousand, three hundred eleven".