Base | Representation |
---|---|
bin | 1011001100101101111000… |
… | …0100100010011101101111 |
3 | 1121121010021020201210111001 |
4 | 2303023132010202131233 |
5 | 3103214213103031111 |
6 | 42104321100341131 |
7 | 2410410101063455 |
oct | 263133604423557 |
9 | 47533236653431 |
10 | 12313102002031 |
11 | 3a17a59095156 |
12 | 146a440b447a7 |
13 | 6b4174a84ccc |
14 | 307d58c3c9d5 |
15 | 16545a97e1c1 |
hex | b32de12276f |
12313102002031 has 2 divisors, whose sum is σ = 12313102002032. Its totient is φ = 12313102002030.
The previous prime is 12313102002001. The next prime is 12313102002043. The reversal of 12313102002031 is 13020020131321.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 12313102002031 - 217 = 12313101870959 is a prime.
It is a super-2 number, since 2×123131020020312 (a number of 27 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (12313102002001) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6156551001015 + 6156551001016.
It is an arithmetic number, because the mean of its divisors is an integer number (6156551001016).
Almost surely, 212313102002031 is an apocalyptic number.
12313102002031 is a deficient number, since it is larger than the sum of its proper divisors (1).
12313102002031 is an equidigital number, since it uses as much as digits as its factorization.
12313102002031 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 216, while the sum is 19.
Adding to 12313102002031 its reverse (13020020131321), we get a palindrome (25333122133352).
The spelling of 12313102002031 in words is "twelve trillion, three hundred thirteen billion, one hundred two million, two thousand, thirty-one".
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