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12313113301103 is a prime number
BaseRepresentation
bin1011001100101101111010…
…1111101001000001101111
31121121010022000222211220012
42303023132233221001233
53103214224001113403
642104322142443435
72410410266113406
oct263133657510157
947533260884805
1012313113301103
113a17a6450232a
12146a44489357b
136b417720cc54
14307d5a54063d
1516545b961ed8
hexb32debe906f

12313113301103 has 2 divisors, whose sum is σ = 12313113301104. Its totient is φ = 12313113301102.

The previous prime is 12313113301081. The next prime is 12313113301211. The reversal of 12313113301103 is 30110331131321.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 12313113301103 - 216 = 12313113235567 is a prime.

It is a super-4 number, since 4×123131133011034 (a number of 53 digits) contains 4444 as substring. Note that it is a super-d number also for d = 2.

It is a Sophie Germain prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (12313110301103) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6156556650551 + 6156556650552.

It is an arithmetic number, because the mean of its divisors is an integer number (6156556650552).

Almost surely, 212313113301103 is an apocalyptic number.

12313113301103 is a deficient number, since it is larger than the sum of its proper divisors (1).

12313113301103 is an equidigital number, since it uses as much as digits as its factorization.

12313113301103 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 486, while the sum is 23.

Adding to 12313113301103 its reverse (30110331131321), we get a palindrome (42423444432424).

The spelling of 12313113301103 in words is "twelve trillion, three hundred thirteen billion, one hundred thirteen million, three hundred one thousand, one hundred three".