Base | Representation |
---|---|
bin | 1011001100101110001111… |
… | …1010011101010111010111 |
3 | 1121121010112002011202222021 |
4 | 2303023203322131113113 |
5 | 3103214413201213444 |
6 | 42104334521314011 |
7 | 2410412401204051 |
oct | 263134372352727 |
9 | 47533462152867 |
10 | 12313200022999 |
11 | 3a17aa9454817 |
12 | 146a469935907 |
13 | 6b418c184a95 |
14 | 307d67c768d1 |
15 | 165464392584 |
hex | b32e3e9d5d7 |
12313200022999 has 2 divisors, whose sum is σ = 12313200023000. Its totient is φ = 12313200022998.
The previous prime is 12313200022987. The next prime is 12313200023009. The reversal of 12313200022999 is 99922000231321.
It is a strong prime.
It is an emirp because it is prime and its reverse (99922000231321) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 12313200022999 - 213 = 12313200014807 is a prime.
It is a super-2 number, since 2×123132000229992 (a number of 27 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (12313200022979) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6156600011499 + 6156600011500.
It is an arithmetic number, because the mean of its divisors is an integer number (6156600011500).
Almost surely, 212313200022999 is an apocalyptic number.
12313200022999 is a deficient number, since it is larger than the sum of its proper divisors (1).
12313200022999 is an equidigital number, since it uses as much as digits as its factorization.
12313200022999 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 104976, while the sum is 43.
The spelling of 12313200022999 in words is "twelve trillion, three hundred thirteen billion, two hundred million, twenty-two thousand, nine hundred ninety-nine".
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