Base | Representation |
---|---|
bin | 1011001100101110010100… |
… | …0110101011100100000111 |
3 | 1121121010120110202220220011 |
4 | 2303023211012223210013 |
5 | 3103214433310112403 |
6 | 42104340513451051 |
7 | 2410413033064024 |
oct | 263134506534407 |
9 | 47533513686804 |
10 | 12313220004103 |
11 | 3a18009761927 |
12 | 146a474570a87 |
13 | 6b419335c715 |
14 | 307d6a79854b |
15 | 165465edca6d |
hex | b32e51ab907 |
12313220004103 has 2 divisors, whose sum is σ = 12313220004104. Its totient is φ = 12313220004102.
The previous prime is 12313220004091. The next prime is 12313220004157. The reversal of 12313220004103 is 30140002231321.
12313220004103 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-12313220004103 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (12313220005103) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6156610002051 + 6156610002052.
It is an arithmetic number, because the mean of its divisors is an integer number (6156610002052).
Almost surely, 212313220004103 is an apocalyptic number.
12313220004103 is a deficient number, since it is larger than the sum of its proper divisors (1).
12313220004103 is an equidigital number, since it uses as much as digits as its factorization.
12313220004103 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 864, while the sum is 22.
Adding to 12313220004103 its reverse (30140002231321), we get a palindrome (42453222235424).
The spelling of 12313220004103 in words is "twelve trillion, three hundred thirteen billion, two hundred twenty million, four thousand, one hundred three".
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