Base | Representation |
---|---|
bin | 10110111011110111… |
… | …11110000011101101 |
3 | 1011210010212112210002 |
4 | 23131323332003231 |
5 | 200204213420023 |
6 | 5353503154045 |
7 | 614065225466 |
oct | 133573760355 |
9 | 34703775702 |
10 | 12313420013 |
11 | 5249671784 |
12 | 24778a5925 |
13 | 1213080a5b |
14 | 84b4c5d6d |
15 | 4c1030b28 |
hex | 2ddefe0ed |
12313420013 has 2 divisors, whose sum is σ = 12313420014. Its totient is φ = 12313420012.
The previous prime is 12313419961. The next prime is 12313420027. The reversal of 12313420013 is 31002431321.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 11838092809 + 475327204 = 108803^2 + 21802^2 .
It is a cyclic number.
It is not a de Polignac number, because 12313420013 - 214 = 12313403629 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (12313420043) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6156710006 + 6156710007.
It is an arithmetic number, because the mean of its divisors is an integer number (6156710007).
Almost surely, 212313420013 is an apocalyptic number.
It is an amenable number.
12313420013 is a deficient number, since it is larger than the sum of its proper divisors (1).
12313420013 is an equidigital number, since it uses as much as digits as its factorization.
12313420013 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 432, while the sum is 20.
Adding to 12313420013 its reverse (31002431321), we get a palindrome (43315851334).
The spelling of 12313420013 in words is "twelve billion, three hundred thirteen million, four hundred twenty thousand, thirteen".
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