Base | Representation |
---|---|
bin | 1011001100101111000111… |
… | …1011010011000110101111 |
3 | 1121121011010110120011010001 |
4 | 2303023301323103012233 |
5 | 3103220403342433033 |
6 | 42104414120325131 |
7 | 2410421254424116 |
oct | 263136173230657 |
9 | 47534113504101 |
10 | 12313435124143 |
11 | 3a1810a13178a |
12 | 146a5146137a7 |
13 | 6b41c8aabb9a |
14 | 307d8b194c7d |
15 | 165479d31e7d |
hex | b32f1ed31af |
12313435124143 has 2 divisors, whose sum is σ = 12313435124144. Its totient is φ = 12313435124142.
The previous prime is 12313435124083. The next prime is 12313435124147. The reversal of 12313435124143 is 34142153431321.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 12313435124143 - 29 = 12313435123631 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (12313435124147) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6156717562071 + 6156717562072.
It is an arithmetic number, because the mean of its divisors is an integer number (6156717562072).
Almost surely, 212313435124143 is an apocalyptic number.
12313435124143 is a deficient number, since it is larger than the sum of its proper divisors (1).
12313435124143 is an equidigital number, since it uses as much as digits as its factorization.
12313435124143 is an evil number, because the sum of its binary digits is even.
The product of its digits is 103680, while the sum is 37.
Adding to 12313435124143 its reverse (34142153431321), we get a palindrome (46455588555464).
It can be divided in two parts, 12313435 and 124143, that added together give a triangular number (12437578 = T4987).
The spelling of 12313435124143 in words is "twelve trillion, three hundred thirteen billion, four hundred thirty-five million, one hundred twenty-four thousand, one hundred forty-three".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.075 sec. • engine limits •