1231344040153 has 2 divisors, whose sum is σ = 1231344040154. Its totient is φ = 1231344040152.

The previous prime is 1231344040141. The next prime is 1231344040181. The reversal of 1231344040153 is 3510404431321.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1231229913664 + 114126489 = 1109608^2 + 10683^2 .

It is a cyclic number.

It is not a de Polignac number, because 1231344040153 - 2⁹ = 1231344039641 is a prime.

It is not a weakly prime, because it can be changed into another prime (1231344040123) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 615672020076 + 615672020077.

It is an arithmetic number, because the mean of its divisors is an integer number (615672020077).

Almost surely, 2^{1231344040153} is an apocalyptic number.

It is an amenable number.

1231344040153 is a deficient number, since it is larger than the sum of its proper divisors (1).

1231344040153 is an equidigital number, since it uses as much as digits as its factorization.

1231344040153 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 17280, while the sum is 31.

Adding to 1231344040153 its reverse (3510404431321), we get a palindrome (4741748471474).

The spelling of 1231344040153 in words is "one trillion, two hundred thirty-one billion, three hundred forty-four million, forty thousand, one hundred fifty-three".