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1231344040141 is a prime number
BaseRepresentation
bin10001111010110001110…
…100101111100011001101
311100201022111001022211001
4101322301310233203031
5130133243033241031
62341401024100301
7154650565435165
oct21726164574315
94321274038731
101231344040141
114352346783a6
1217a786764691
138c166267517
14438512795a5
152206b803861
hex11eb1d2f8cd

1231344040141 has 2 divisors, whose sum is σ = 1231344040142. Its totient is φ = 1231344040140.

The previous prime is 1231344040139. The next prime is 1231344040153. The reversal of 1231344040141 is 1410404431321.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 962419860900 + 268924179241 = 981030^2 + 518579^2 .

It is a cyclic number.

It is not a de Polignac number, because 1231344040141 - 21 = 1231344040139 is a prime.

Together with 1231344040139, it forms a pair of twin primes.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1231344040181) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 615672020070 + 615672020071.

It is an arithmetic number, because the mean of its divisors is an integer number (615672020071).

Almost surely, 21231344040141 is an apocalyptic number.

It is an amenable number.

1231344040141 is a deficient number, since it is larger than the sum of its proper divisors (1).

1231344040141 is an equidigital number, since it uses as much as digits as its factorization.

1231344040141 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 4608, while the sum is 28.

Adding to 1231344040141 its reverse (1410404431321), we get a palindrome (2641748471462).

The spelling of 1231344040141 in words is "one trillion, two hundred thirty-one billion, three hundred forty-four million, forty thousand, one hundred forty-one".