Base | Representation |
---|---|
bin | 1011001100110001101011… |
… | …1111100101010111001001 |
3 | 1121121012220111000102121221 |
4 | 2303030122333211113021 |
5 | 3103223311233111403 |
6 | 42105010332002041 |
7 | 2410444321636036 |
oct | 263143277452711 |
9 | 47535814012557 |
10 | 12314124113353 |
11 | 3a18433040557 |
12 | 146a687300321 |
13 | 6b42a87645ca |
14 | 3080148a438d |
15 | 1654ba57bdbd |
hex | b331afe55c9 |
12314124113353 has 2 divisors, whose sum is σ = 12314124113354. Its totient is φ = 12314124113352.
The previous prime is 12314124113327. The next prime is 12314124113381. The reversal of 12314124113353 is 35331142141321.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 12245996327184 + 68127786169 = 3499428^2 + 261013^2 .
It is a cyclic number.
It is not a de Polignac number, because 12314124113353 - 241 = 10115100857801 is a prime.
It is not a weakly prime, because it can be changed into another prime (12314124113653) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6157062056676 + 6157062056677.
It is an arithmetic number, because the mean of its divisors is an integer number (6157062056677).
Almost surely, 212314124113353 is an apocalyptic number.
It is an amenable number.
12314124113353 is a deficient number, since it is larger than the sum of its proper divisors (1).
12314124113353 is an equidigital number, since it uses as much as digits as its factorization.
12314124113353 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 25920, while the sum is 34.
Adding to 12314124113353 its reverse (35331142141321), we get a palindrome (47645266254674).
The spelling of 12314124113353 in words is "twelve trillion, three hundred fourteen billion, one hundred twenty-four million, one hundred thirteen thousand, three hundred fifty-three".
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