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123141520031 is a prime number
BaseRepresentation
bin111001010101111001…
…1100111101010011111
3102202211221111100211012
41302223303213222133
54004143212120111
6132323114045435
711616363435635
oct1625363475237
9382757440735
10123141520031
11482511a5672
121ba47a1987b
13b7c5cbba6a
145d6266b355
15330aba148b
hex1cabce7a9f

123141520031 has 2 divisors, whose sum is σ = 123141520032. Its totient is φ = 123141520030.

The previous prime is 123141520003. The next prime is 123141520057. The reversal of 123141520031 is 130025141321.

It is a strong prime.

It is an emirp because it is prime and its reverse (130025141321) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 123141520031 - 218 = 123141257887 is a prime.

It is a super-2 number, since 2×1231415200312 (a number of 23 digits) contains 22 as substring.

It is a Sophie Germain prime.

It is a junction number, because it is equal to n+sod(n) for n = 123141519979 and 123141520006.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (123141520091) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 61570760015 + 61570760016.

It is an arithmetic number, because the mean of its divisors is an integer number (61570760016).

Almost surely, 2123141520031 is an apocalyptic number.

123141520031 is a deficient number, since it is larger than the sum of its proper divisors (1).

123141520031 is an equidigital number, since it uses as much as digits as its factorization.

123141520031 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 720, while the sum is 23.

Adding to 123141520031 its reverse (130025141321), we get a palindrome (253166661352).

The spelling of 123141520031 in words is "one hundred twenty-three billion, one hundred forty-one million, five hundred twenty thousand, thirty-one".