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123144134203957 is a prime number
BaseRepresentation
bin11011111111111110111010…
…011000000001101000110101
3121011000110112102222111210211
4123333332322120001220311
5112120043141324011312
61113523345000345421
734636604305024306
oct3377767230015065
9534013472874724
10123144134203957
1136268152440709
121198a1a9475271
13539359919b399
14225a2ca6807ad
15e383dca003a7
hex6fffba601a35

123144134203957 has 2 divisors, whose sum is σ = 123144134203958. Its totient is φ = 123144134203956.

The previous prime is 123144134203889. The next prime is 123144134204011. The reversal of 123144134203957 is 759302431441321.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 62495333349201 + 60648800854756 = 7905399^2 + 7787734^2 .

It is a cyclic number.

It is not a de Polignac number, because 123144134203957 - 231 = 123141986720309 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 123144134203957.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (123144134203157) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 61572067101978 + 61572067101979.

It is an arithmetic number, because the mean of its divisors is an integer number (61572067101979).

Almost surely, 2123144134203957 is an apocalyptic number.

It is an amenable number.

123144134203957 is a deficient number, since it is larger than the sum of its proper divisors (1).

123144134203957 is an equidigital number, since it uses as much as digits as its factorization.

123144134203957 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 2177280, while the sum is 49.

The spelling of 123144134203957 in words is "one hundred twenty-three trillion, one hundred forty-four billion, one hundred thirty-four million, two hundred three thousand, nine hundred fifty-seven".