Base | Representation |
---|---|
bin | 1011001100110110100010… |
… | …0111101001001011001111 |
3 | 1121121100021020121111212112 |
4 | 2303031220213221023033 |
5 | 3103233443133212432 |
6 | 42105343453454235 |
7 | 2410521514463102 |
oct | 263155047511317 |
9 | 47540236544775 |
10 | 12315426460367 |
11 | 3a18a411a10a8 |
12 | 146a98b4a137b |
13 | 6b4455511944 |
14 | 3080d9836739 |
15 | 165544a827b2 |
hex | b33689e92cf |
12315426460367 has 2 divisors, whose sum is σ = 12315426460368. Its totient is φ = 12315426460366.
The previous prime is 12315426460283. The next prime is 12315426460433. The reversal of 12315426460367 is 76306462451321.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 12315426460367 - 230 = 12314352718543 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (12315426465367) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6157713230183 + 6157713230184.
It is an arithmetic number, because the mean of its divisors is an integer number (6157713230184).
Almost surely, 212315426460367 is an apocalyptic number.
12315426460367 is a deficient number, since it is larger than the sum of its proper divisors (1).
12315426460367 is an equidigital number, since it uses as much as digits as its factorization.
12315426460367 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 4354560, while the sum is 50.
The spelling of 12315426460367 in words is "twelve trillion, three hundred fifteen billion, four hundred twenty-six million, four hundred sixty thousand, three hundred sixty-seven".
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