Base | Representation |
---|---|
bin | 10001111011011010000… |
… | …111011000000100101001 |
3 | 11100210001121000022201221 |
4 | 101323122013120010221 |
5 | 130141134110411403 |
6 | 2341552052342041 |
7 | 155003414216443 |
oct | 21733207300451 |
9 | 4323047008657 |
10 | 1232020013353 |
11 | 4355511a7048 |
12 | 17a935014921 |
13 | 8c24331367c |
14 | 438b6d5b493 |
15 | 220aad2bdbd |
hex | 11eda1d8129 |
1232020013353 has 2 divisors, whose sum is σ = 1232020013354. Its totient is φ = 1232020013352.
The previous prime is 1232020013333. The next prime is 1232020013407. The reversal of 1232020013353 is 3533100202321.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 1223795700009 + 8224313344 = 1106253^2 + 90688^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1232020013353 is a prime.
It is not a weakly prime, because it can be changed into another prime (1232020013333) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 616010006676 + 616010006677.
It is an arithmetic number, because the mean of its divisors is an integer number (616010006677).
Almost surely, 21232020013353 is an apocalyptic number.
It is an amenable number.
1232020013353 is a deficient number, since it is larger than the sum of its proper divisors (1).
1232020013353 is an equidigital number, since it uses as much as digits as its factorization.
1232020013353 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 3240, while the sum is 25.
Adding to 1232020013353 its reverse (3533100202321), we get a palindrome (4765120215674).
The spelling of 1232020013353 in words is "one trillion, two hundred thirty-two billion, twenty million, thirteen thousand, three hundred fifty-three".
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