Base | Representation |
---|---|
bin | 11100000000110110001000… |
… | …000111000101001100011111 |
3 | 121011020010120012111112011201 |
4 | 130000312020013011030133 |
5 | 112122031101113142143 |
6 | 1114010511530300331 |
7 | 34644103416526435 |
oct | 3400661007051437 |
9 | 534203505445151 |
10 | 123203420443423 |
11 | 36290305a2a931 |
12 | 119997942876a7 |
13 | 5399056aaba58 |
14 | 225d112416d55 |
15 | e39c0c76364d |
hex | 700d881c531f |
123203420443423 has 2 divisors, whose sum is σ = 123203420443424. Its totient is φ = 123203420443422.
The previous prime is 123203420443387. The next prime is 123203420443469. The reversal of 123203420443423 is 324344024302321.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 123203420443423 - 213 = 123203420435231 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (123203420443823) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 61601710221711 + 61601710221712.
It is an arithmetic number, because the mean of its divisors is an integer number (61601710221712).
Almost surely, 2123203420443423 is an apocalyptic number.
123203420443423 is a deficient number, since it is larger than the sum of its proper divisors (1).
123203420443423 is an equidigital number, since it uses as much as digits as its factorization.
123203420443423 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 331776, while the sum is 37.
Adding to 123203420443423 its reverse (324344024302321), we get a palindrome (447547444745744).
The spelling of 123203420443423 in words is "one hundred twenty-three trillion, two hundred three billion, four hundred twenty million, four hundred forty-three thousand, four hundred twenty-three".
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