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1232113340131 is a prime number
BaseRepresentation
bin10001111011011111101…
…011011000111011100011
311100210022002121211000021
4101323133223120323203
5130141332003341011
62342005224534311
7155005626406252
oct21733753307343
94323262554007
101232113340131
1143559994a913
1217a960321397
138c25975b90b
14438c54d2799
15220b4114471
hex11edfad8ee3

1232113340131 has 2 divisors, whose sum is σ = 1232113340132. Its totient is φ = 1232113340130.

The previous prime is 1232113340119. The next prime is 1232113340137. The reversal of 1232113340131 is 1310433112321.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 1232113340131 - 211 = 1232113338083 is a prime.

It is a super-2 number, since 2×12321133401312 (a number of 25 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 1232113340096 and 1232113340105.

It is not a weakly prime, because it can be changed into another prime (1232113340137) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 616056670065 + 616056670066.

It is an arithmetic number, because the mean of its divisors is an integer number (616056670066).

Almost surely, 21232113340131 is an apocalyptic number.

1232113340131 is a deficient number, since it is larger than the sum of its proper divisors (1).

1232113340131 is an equidigital number, since it uses as much as digits as its factorization.

1232113340131 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1296, while the sum is 25.

Adding to 1232113340131 its reverse (1310433112321), we get a palindrome (2542546452452).

The spelling of 1232113340131 in words is "one trillion, two hundred thirty-two billion, one hundred thirteen million, three hundred forty thousand, one hundred thirty-one".