Base | Representation |
---|---|
bin | 1011001101001100000011… |
… | …0100111100111001000111 |
3 | 1121121220011201000100002112 |
4 | 2303103000310330321013 |
5 | 3103332310013430203 |
6 | 42112140504531235 |
7 | 2411114566061153 |
oct | 263230064747107 |
9 | 47556151010075 |
10 | 12321201311303 |
11 | 3a20434a22085 |
12 | 146bb21480b1b |
13 | 6b4b65a593c1 |
14 | 3084c6798063 |
15 | 165781a446d8 |
hex | b34c0d3ce47 |
12321201311303 has 2 divisors, whose sum is σ = 12321201311304. Its totient is φ = 12321201311302.
The previous prime is 12321201311231. The next prime is 12321201311333. The reversal of 12321201311303 is 30311310212321.
12321201311303 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 12321201311303 - 222 = 12321197116999 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (12321201311333) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6160600655651 + 6160600655652.
It is an arithmetic number, because the mean of its divisors is an integer number (6160600655652).
Almost surely, 212321201311303 is an apocalyptic number.
12321201311303 is a deficient number, since it is larger than the sum of its proper divisors (1).
12321201311303 is an equidigital number, since it uses as much as digits as its factorization.
12321201311303 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 648, while the sum is 23.
Adding to 12321201311303 its reverse (30311310212321), we get a palindrome (42632511523624).
The spelling of 12321201311303 in words is "twelve trillion, three hundred twenty-one billion, two hundred one million, three hundred eleven thousand, three hundred three".
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