Base | Representation |
---|---|
bin | 1011001101001100000100… |
… | …1001001111100011110111 |
3 | 1121121220012002000120212021 |
4 | 2303103001021033203313 |
5 | 3103332312344140042 |
6 | 42112141214534011 |
7 | 2411114662224355 |
oct | 263230111174367 |
9 | 47556162016767 |
10 | 12321206630647 |
11 | 3a20437a25632 |
12 | 146bb23207307 |
13 | 6b4b66b9c645 |
14 | 3084c73807d5 |
15 | 165782245867 |
hex | b34c124f8f7 |
12321206630647 has 2 divisors, whose sum is σ = 12321206630648. Its totient is φ = 12321206630646.
The previous prime is 12321206630597. The next prime is 12321206630683. The reversal of 12321206630647 is 74603660212321.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 12321206630647 - 215 = 12321206597879 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (12321206640647) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6160603315323 + 6160603315324.
It is an arithmetic number, because the mean of its divisors is an integer number (6160603315324).
Almost surely, 212321206630647 is an apocalyptic number.
12321206630647 is a deficient number, since it is larger than the sum of its proper divisors (1).
12321206630647 is an equidigital number, since it uses as much as digits as its factorization.
12321206630647 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 435456, while the sum is 43.
Adding to 12321206630647 its reverse (74603660212321), we get a palindrome (86924866842968).
The spelling of 12321206630647 in words is "twelve trillion, three hundred twenty-one billion, two hundred six million, six hundred thirty thousand, six hundred forty-seven".
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