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12321411200047 is a prime number
BaseRepresentation
bin1011001101001100110101…
…0101100111010000101111
31121121220201022221210022201
42303103031111213100233
53103333222231400142
642112213403322331
72411123025102535
oct263231525472057
947556638853281
1012321411200047
113a20532449654
12146bb7b8203a7
136b4b9a396721
143085065d2155
151657951a3ab7
hexb34cd56742f

12321411200047 has 2 divisors, whose sum is σ = 12321411200048. Its totient is φ = 12321411200046.

The previous prime is 12321411200027. The next prime is 12321411200107. The reversal of 12321411200047 is 74000211412321.

It is a weak prime.

It is an emirp because it is prime and its reverse (74000211412321) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 12321411200047 - 243 = 3525318177839 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 12321411199988 and 12321411200024.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (12321411200027) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6160705600023 + 6160705600024.

It is an arithmetic number, because the mean of its divisors is an integer number (6160705600024).

Almost surely, 212321411200047 is an apocalyptic number.

12321411200047 is a deficient number, since it is larger than the sum of its proper divisors (1).

12321411200047 is an equidigital number, since it uses as much as digits as its factorization.

12321411200047 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 2688, while the sum is 28.

Adding to 12321411200047 its reverse (74000211412321), we get a palindrome (86321622612368).

The spelling of 12321411200047 in words is "twelve trillion, three hundred twenty-one billion, four hundred eleven million, two hundred thousand, forty-seven".