Base | Representation |
---|---|
bin | 10001111011100101100… |
… | …001000111010111000011 |
3 | 11100210112220222012102122 |
4 | 101323211201013113003 |
5 | 130142032043410034 |
6 | 2342023044434455 |
7 | 155011226214614 |
oct | 21734541072703 |
9 | 4323486865378 |
10 | 1232211310019 |
11 | 43563a185068 |
12 | 17a9890a8a2b |
13 | 8c273b41371 |
14 | 438d4515c0b |
15 | 220bca1762e |
hex | 11ee58475c3 |
1232211310019 has 2 divisors, whose sum is σ = 1232211310020. Its totient is φ = 1232211310018.
The previous prime is 1232211309991. The next prime is 1232211310021. The reversal of 1232211310019 is 9100131122321.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1232211310019 is a prime.
It is a super-2 number, since 2×12322113100192 (a number of 25 digits) contains 22 as substring.
Together with 1232211310021, it forms a pair of twin primes.
It is a Chen prime.
It is a self number, because there is not a number n which added to its sum of digits gives 1232211310019.
It is not a weakly prime, because it can be changed into another prime (1232211310069) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 616105655009 + 616105655010.
It is an arithmetic number, because the mean of its divisors is an integer number (616105655010).
Almost surely, 21232211310019 is an apocalyptic number.
1232211310019 is a deficient number, since it is larger than the sum of its proper divisors (1).
1232211310019 is an equidigital number, since it uses as much as digits as its factorization.
1232211310019 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 648, while the sum is 26.
The spelling of 1232211310019 in words is "one trillion, two hundred thirty-two billion, two hundred eleven million, three hundred ten thousand, nineteen".
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