Base | Representation |
---|---|
bin | 1011001101010011111010… |
… | …1001000000111011011011 |
3 | 1121122002121210212002101001 |
4 | 2303110332221000323123 |
5 | 3103401120400030243 |
6 | 42113130150405431 |
7 | 2411221106426113 |
oct | 263247651007333 |
9 | 47562553762331 |
10 | 12323312111323 |
11 | 3a21318467404 |
12 | 1470410360877 |
13 | 6b5111158cb5 |
14 | 308646c56043 |
15 | 165856ee1a4d |
hex | b353ea40edb |
12323312111323 has 2 divisors, whose sum is σ = 12323312111324. Its totient is φ = 12323312111322.
The previous prime is 12323312111267. The next prime is 12323312111351. The reversal of 12323312111323 is 32311121332321.
It is an a-pointer prime, because the next prime (12323312111351) can be obtained adding 12323312111323 to its sum of digits (28).
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 12323312111323 - 237 = 12185873157851 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 12323312111291 and 12323312111300.
It is not a weakly prime, because it can be changed into another prime (12323312171323) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6161656055661 + 6161656055662.
It is an arithmetic number, because the mean of its divisors is an integer number (6161656055662).
Almost surely, 212323312111323 is an apocalyptic number.
12323312111323 is a deficient number, since it is larger than the sum of its proper divisors (1).
12323312111323 is an equidigital number, since it uses as much as digits as its factorization.
12323312111323 is an evil number, because the sum of its binary digits is even.
The product of its digits is 3888, while the sum is 28.
Adding to 12323312111323 its reverse (32311121332321), we get a palindrome (44634433443644).
The spelling of 12323312111323 in words is "twelve trillion, three hundred twenty-three billion, three hundred twelve million, one hundred eleven thousand, three hundred twenty-three".
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