Base | Representation |
---|---|
bin | 1011001101010011111101… |
… | …0111001111101100100111 |
3 | 1121122002122122122210200012 |
4 | 2303110333113033230213 |
5 | 3103401132000333224 |
6 | 42113131302240435 |
7 | 2411221314432605 |
oct | 263247727175447 |
9 | 47562578583605 |
10 | 12323324230439 |
11 | 3a21324294702 |
12 | 147041442611b |
13 | 6b5113810281 |
14 | 3086486cc875 |
15 | 1658580d780e |
hex | b353f5cfb27 |
12323324230439 has 2 divisors, whose sum is σ = 12323324230440. Its totient is φ = 12323324230438.
The previous prime is 12323324230391. The next prime is 12323324230463. The reversal of 12323324230439 is 93403242332321.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 12323324230439 - 216 = 12323324164903 is a prime.
It is a Sophie Germain prime.
It is a junction number, because it is equal to n+sod(n) for n = 12323324230396 and 12323324230405.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (12323324230039) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6161662115219 + 6161662115220.
It is an arithmetic number, because the mean of its divisors is an integer number (6161662115220).
Almost surely, 212323324230439 is an apocalyptic number.
12323324230439 is a deficient number, since it is larger than the sum of its proper divisors (1).
12323324230439 is an equidigital number, since it uses as much as digits as its factorization.
12323324230439 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 559872, while the sum is 41.
The spelling of 12323324230439 in words is "twelve trillion, three hundred twenty-three billion, three hundred twenty-four million, two hundred thirty thousand, four hundred thirty-nine".
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