Base | Representation |
---|---|
bin | 10001111011101101110… |
… | …011101101001100011011 |
3 | 11100210220121200202210211 |
4 | 101323231303231030123 |
5 | 130142323200320212 |
6 | 2342044533551551 |
7 | 155014535401564 |
oct | 21735563551433 |
9 | 4323817622724 |
10 | 1232350401307 |
11 | 435700746443 |
12 | 17aa077a55b7 |
13 | 8c2968c0bbc |
14 | 43908ba116b |
15 | 220c9d3e9a7 |
hex | 11eedced31b |
1232350401307 has 2 divisors, whose sum is σ = 1232350401308. Its totient is φ = 1232350401306.
The previous prime is 1232350401299. The next prime is 1232350401353. The reversal of 1232350401307 is 7031040532321.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 1232350401307 - 23 = 1232350401299 is a prime.
It is not a weakly prime, because it can be changed into another prime (1232350471307) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 616175200653 + 616175200654.
It is an arithmetic number, because the mean of its divisors is an integer number (616175200654).
Almost surely, 21232350401307 is an apocalyptic number.
1232350401307 is a deficient number, since it is larger than the sum of its proper divisors (1).
1232350401307 is an equidigital number, since it uses as much as digits as its factorization.
1232350401307 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 15120, while the sum is 31.
Adding to 1232350401307 its reverse (7031040532321), we get a palindrome (8263390933628).
The spelling of 1232350401307 in words is "one trillion, two hundred thirty-two billion, three hundred fifty million, four hundred one thousand, three hundred seven".
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