Base | Representation |
---|---|
bin | 10001111011101101110… |
… | …011101101001101001001 |
3 | 11100210220121200202212112 |
4 | 101323231303231031021 |
5 | 130142323200320403 |
6 | 2342044533552105 |
7 | 155014535401661 |
oct | 21735563551511 |
9 | 4323817622775 |
10 | 1232350401353 |
11 | 435700746485 |
12 | 17aa077a5635 |
13 | 8c2968c0c26 |
14 | 43908ba11a1 |
15 | 220c9d3e9d8 |
hex | 11eedced349 |
1232350401353 has 2 divisors, whose sum is σ = 1232350401354. Its totient is φ = 1232350401352.
The previous prime is 1232350401307. The next prime is 1232350401409. The reversal of 1232350401353 is 3531040532321.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 838006592329 + 394343809024 = 915427^2 + 627968^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1232350401353 is a prime.
It is not a weakly prime, because it can be changed into another prime (1232358401353) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 616175200676 + 616175200677.
It is an arithmetic number, because the mean of its divisors is an integer number (616175200677).
Almost surely, 21232350401353 is an apocalyptic number.
It is an amenable number.
1232350401353 is a deficient number, since it is larger than the sum of its proper divisors (1).
1232350401353 is an equidigital number, since it uses as much as digits as its factorization.
1232350401353 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 32400, while the sum is 32.
Adding to 1232350401353 its reverse (3531040532321), we get a palindrome (4763390933674).
The spelling of 1232350401353 in words is "one trillion, two hundred thirty-two billion, three hundred fifty million, four hundred one thousand, three hundred fifty-three".
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