Base | Representation |
---|---|
bin | 1011001101010100110111… |
… | …0000001100001001000001 |
3 | 1121122010021110221012201211 |
4 | 2303111031300030021001 |
5 | 3103402130301303442 |
6 | 42113211244530121 |
7 | 2411230305451303 |
oct | 263251560141101 |
9 | 47563243835654 |
10 | 12323565650497 |
11 | 3a21438598112 |
12 | 1470481250941 |
13 | 6b515183a58a |
14 | 30866c7b3973 |
15 | 16586e3c4617 |
hex | b354dc0c241 |
12323565650497 has 2 divisors, whose sum is σ = 12323565650498. Its totient is φ = 12323565650496.
The previous prime is 12323565650491. The next prime is 12323565650521. The reversal of 12323565650497 is 79405656532321.
It is a happy number.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 12208098892081 + 115466758416 = 3494009^2 + 339804^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-12323565650497 is a prime.
It is not a weakly prime, because it can be changed into another prime (12323565650491) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6161782825248 + 6161782825249.
It is an arithmetic number, because the mean of its divisors is an integer number (6161782825249).
Almost surely, 212323565650497 is an apocalyptic number.
It is an amenable number.
12323565650497 is a deficient number, since it is larger than the sum of its proper divisors (1).
12323565650497 is an equidigital number, since it uses as much as digits as its factorization.
12323565650497 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 40824000, while the sum is 58.
The spelling of 12323565650497 in words is "twelve trillion, three hundred twenty-three billion, five hundred sixty-five million, six hundred fifty thousand, four hundred ninety-seven".
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