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1232358401353 is a prime number
BaseRepresentation
bin10001111011101110010…
…010001110010101001001
311100210221011202012210211
4101323232102032111021
5130142332222320403
62342045421241121
7155014663401412
oct21735622162511
94323834665724
101232358401353
1143570520aa52
1217aa0a4031a1
138c298462361
1443909c84809
15220ca8c006d
hex11eee48e549

1232358401353 has 2 divisors, whose sum is σ = 1232358401354. Its totient is φ = 1232358401352.

The previous prime is 1232358401321. The next prime is 1232358401387. The reversal of 1232358401353 is 3531048532321.

It is a happy number.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 617305633344 + 615052768009 = 785688^2 + 784253^2 .

It is an emirp because it is prime and its reverse (3531048532321) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1232358401353 - 25 = 1232358401321 is a prime.

It is a super-3 number, since 3×12323584013533 (a number of 37 digits) contains 333 as substring.

It is not a weakly prime, because it can be changed into another prime (1232358401753) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 616179200676 + 616179200677.

It is an arithmetic number, because the mean of its divisors is an integer number (616179200677).

Almost surely, 21232358401353 is an apocalyptic number.

It is an amenable number.

1232358401353 is a deficient number, since it is larger than the sum of its proper divisors (1).

1232358401353 is an equidigital number, since it uses as much as digits as its factorization.

1232358401353 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 259200, while the sum is 40.

The spelling of 1232358401353 in words is "one trillion, two hundred thirty-two billion, three hundred fifty-eight million, four hundred one thousand, three hundred fifty-three".