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123241355253151 is a prime number
BaseRepresentation
bin11100000001011001011101…
…001100111001010110011111
3121011100202110221112112012121
4130001121131030321112133
5112123141243421100101
61114040144053043411
734646615446223362
oct3401313514712637
9534322427475177
10123241355253151
11362a5402165953
12119a5000626567
13539c7c1040725
142260cb05da0d9
15e3abcccac0a1
hex70165d33959f

123241355253151 has 2 divisors, whose sum is σ = 123241355253152. Its totient is φ = 123241355253150.

The previous prime is 123241355253043. The next prime is 123241355253157. The reversal of 123241355253151 is 151352553142321.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-123241355253151 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 123241355253098 and 123241355253107.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (123241355253157) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 61620677626575 + 61620677626576.

It is an arithmetic number, because the mean of its divisors is an integer number (61620677626576).

Almost surely, 2123241355253151 is an apocalyptic number.

123241355253151 is a deficient number, since it is larger than the sum of its proper divisors (1).

123241355253151 is an equidigital number, since it uses as much as digits as its factorization.

123241355253151 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 540000, while the sum is 43.

The spelling of 123241355253151 in words is "one hundred twenty-three trillion, two hundred forty-one billion, three hundred fifty-five million, two hundred fifty-three thousand, one hundred fifty-one".