Base | Representation |
---|---|
bin | 11100000001011010100010… |
… | …000010010111100010111111 |
3 | 121011100212110102121220021111 |
4 | 130001122202002113202333 |
5 | 112123201130042334101 |
6 | 1114040454425542451 |
7 | 34646656201360441 |
oct | 3401324202274277 |
9 | 534325412556244 |
10 | 123242510121151 |
11 | 362a5945046313 |
12 | 119a5283344a27 |
13 | 539c946392485 |
14 | 2260d7db3c491 |
15 | e3ac49380251 |
hex | 7016a20978bf |
123242510121151 has 32 divisors (see below), whose sum is σ = 127979126413056. Its totient is φ = 118589184000000.
The previous prime is 123242510121149. The next prime is 123242510121161. The reversal of 123242510121151 is 151121015242321.
It is a happy number.
It is a cyclic number.
It is not a de Polignac number, because 123242510121151 - 21 = 123242510121149 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (123242510121161) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 864782401 + ... + 864924901.
It is an arithmetic number, because the mean of its divisors is an integer number (3999347700408).
Almost surely, 2123242510121151 is an apocalyptic number.
123242510121151 is a deficient number, since it is larger than the sum of its proper divisors (4736616291905).
123242510121151 is a wasteful number, since it uses less digits than its factorization.
123242510121151 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 143443.
The product of its (nonzero) digits is 4800, while the sum is 31.
Adding to 123242510121151 its reverse (151121015242321), we get a palindrome (274363525363472).
The spelling of 123242510121151 in words is "one hundred twenty-three trillion, two hundred forty-two billion, five hundred ten million, one hundred twenty-one thousand, one hundred fifty-one".
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