Base | Representation |
---|---|
bin | 1011001101011000000000… |
… | …1001110000010011010011 |
3 | 1121122012110102000020102222 |
4 | 2303112000021300103103 |
5 | 3103410343232304021 |
6 | 42113431212131255 |
7 | 2411260253561162 |
oct | 263260011602323 |
9 | 47565412006388 |
10 | 12324411213011 |
11 | 3a21831918807 |
12 | 1470678466b2b |
13 | 6b5257a83b21 |
14 | 30870cbdd3d9 |
15 | 1658bd74b6ab |
hex | b35802704d3 |
12324411213011 has 2 divisors, whose sum is σ = 12324411213012. Its totient is φ = 12324411213010.
The previous prime is 12324411212989. The next prime is 12324411213043. The reversal of 12324411213011 is 11031211442321.
It is a happy number.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 12324411213011 - 214 = 12324411196627 is a prime.
It is a super-2 number, since 2×123244112130112 (a number of 27 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (12324411213511) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6162205606505 + 6162205606506.
It is an arithmetic number, because the mean of its divisors is an integer number (6162205606506).
Almost surely, 212324411213011 is an apocalyptic number.
12324411213011 is a deficient number, since it is larger than the sum of its proper divisors (1).
12324411213011 is an equidigital number, since it uses as much as digits as its factorization.
12324411213011 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1152, while the sum is 26.
Adding to 12324411213011 its reverse (11031211442321), we get a palindrome (23355622655332).
The spelling of 12324411213011 in words is "twelve trillion, three hundred twenty-four billion, four hundred eleven million, two hundred thirteen thousand, eleven".
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