12325146410081 has 2 divisors, whose sum is σ = 12325146410082. Its totient is φ = 12325146410080.

The previous prime is 12325146410029. The next prime is 12325146410107. The reversal of 12325146410081 is 18001464152321.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 8376341544481 + 3948804865600 = 2894191^2 + 1987160^2 .

It is a cyclic number.

It is not a de Polignac number, because 12325146410081 - 2¹⁴ = 12325146393697 is a prime.

It is a super-3 number, since 3×12325146410081³ (a number of 40 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is not a weakly prime, because it can be changed into another prime (12325146410011) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6162573205040 + 6162573205041.

It is an arithmetic number, because the mean of its divisors is an integer number (6162573205041).

Almost surely, 2^{12325146410081} is an apocalyptic number.

It is an amenable number.

12325146410081 is a deficient number, since it is larger than the sum of its proper divisors (1).

12325146410081 is an equidigital number, since it uses as much as digits as its factorization.

12325146410081 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 46080, while the sum is 38.

The spelling of 12325146410081 in words is "twelve trillion, three hundred twenty-five billion, one hundred forty-six million, four hundred ten thousand, eighty-one".