Base | Representation |
---|---|
bin | 11100000001100110101001… |
… | …000100011101010010000010 |
3 | 121011102010000121212011022122 |
4 | 130001212221010131102002 |
5 | 112123404242312330310 |
6 | 1114050445003004242 |
7 | 34650626341203320 |
oct | 3401465104352202 |
9 | 534363017764278 |
10 | 123255513011330 |
11 | 36300407915147 |
12 | 119a78b1b09682 |
13 | 53a0c3923682b |
14 | 2261854a1ad10 |
15 | e3b25aba3555 |
hex | 7019a911d482 |
123255513011330 has 32 divisors (see below), whose sum is σ = 253664009786880. Its totient is φ = 42240731100480.
The previous prime is 123255513011321. The next prime is 123255513011387. The reversal of 123255513011330 is 33110315552321.
It is a super-2 number, since 2×1232555130113302 (a number of 29 digits) contains 22 as substring.
It is a Harshad number since it is a multiple of its sum of digits (35).
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 381127466 + ... + 381450725.
It is an arithmetic number, because the mean of its divisors is an integer number (7927000305840).
Almost surely, 2123255513011330 is an apocalyptic number.
123255513011330 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
123255513011330 is an abundant number, since it is smaller than the sum of its proper divisors (130408496775550).
123255513011330 is a wasteful number, since it uses less digits than its factorization.
123255513011330 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 762580514.
The product of its (nonzero) digits is 40500, while the sum is 35.
Adding to 123255513011330 its reverse (33110315552321), we get a palindrome (156365828563651).
The spelling of 123255513011330 in words is "one hundred twenty-three trillion, two hundred fifty-five billion, five hundred thirteen million, eleven thousand, three hundred thirty".
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