Base | Representation |
---|---|
bin | 1011001101011101000100… |
… | …0011011011110001010011 |
3 | 1121122022222000000002122002 |
4 | 2303113101003123301103 |
5 | 3103421133214314142 |
6 | 42114214015504215 |
7 | 2411336014451642 |
oct | 263272103336123 |
9 | 47568860002562 |
10 | 12325768510547 |
11 | 3a22368aa0508 |
12 | 1470996b2806b |
13 | 6b541303096b |
14 | 3087db197359 |
15 | 16594c9a8a32 |
hex | b35d10dbc53 |
12325768510547 has 2 divisors, whose sum is σ = 12325768510548. Its totient is φ = 12325768510546.
The previous prime is 12325768510519. The next prime is 12325768510577. The reversal of 12325768510547 is 74501586752321.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 12325768510547 - 212 = 12325768506451 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 12325768510492 and 12325768510501.
It is not a weakly prime, because it can be changed into another prime (12325768510507) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6162884255273 + 6162884255274.
It is an arithmetic number, because the mean of its divisors is an integer number (6162884255274).
Almost surely, 212325768510547 is an apocalyptic number.
12325768510547 is a deficient number, since it is larger than the sum of its proper divisors (1).
12325768510547 is an equidigital number, since it uses as much as digits as its factorization.
12325768510547 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 14112000, while the sum is 56.
The spelling of 12325768510547 in words is "twelve trillion, three hundred twenty-five billion, seven hundred sixty-eight million, five hundred ten thousand, five hundred forty-seven".
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