Base | Representation |
---|---|
bin | 10001111100000001100… |
… | …010001111010111100011 |
3 | 11100211202200110120101212 |
4 | 101330001202033113203 |
5 | 130144012412221021 |
6 | 2342141435420335 |
7 | 155025664511303 |
oct | 21740142172743 |
9 | 4324680416355 |
10 | 1232681367011 |
11 | 43586054a916 |
12 | 17aa9a5b46ab |
13 | 8c31a3413b3 |
14 | 4393ab15603 |
15 | 220e8e1885b |
hex | 11f0188f5e3 |
1232681367011 has 2 divisors, whose sum is σ = 1232681367012. Its totient is φ = 1232681367010.
The previous prime is 1232681366993. The next prime is 1232681367013. The reversal of 1232681367011 is 1107631862321.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1232681367011 - 218 = 1232681104867 is a prime.
It is a super-2 number, since 2×12326813670112 (a number of 25 digits) contains 22 as substring.
Together with 1232681367013, it forms a pair of twin primes.
It is a Chen prime.
It is a self number, because there is not a number n which added to its sum of digits gives 1232681367011.
It is not a weakly prime, because it can be changed into another prime (1232681367013) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 616340683505 + 616340683506.
It is an arithmetic number, because the mean of its divisors is an integer number (616340683506).
Almost surely, 21232681367011 is an apocalyptic number.
1232681367011 is a deficient number, since it is larger than the sum of its proper divisors (1).
1232681367011 is an equidigital number, since it uses as much as digits as its factorization.
1232681367011 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 72576, while the sum is 41.
The spelling of 1232681367011 in words is "one trillion, two hundred thirty-two billion, six hundred eighty-one million, three hundred sixty-seven thousand, eleven".
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