1233000040147 has 2 divisors, whose sum is σ = 1233000040148. Its totient is φ = 1233000040146.

The previous prime is 1233000040087. The next prime is 1233000040163. The reversal of 1233000040147 is 7410400003321.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 1233000040147 - 2¹¹ = 1233000038099 is a prime.

It is a super-2 number, since 2×1233000040147² (a number of 25 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (1233000640147) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 616500020073 + 616500020074.

It is an arithmetic number, because the mean of its divisors is an integer number (616500020074).

Almost surely, 2^{1233000040147} is an apocalyptic number.

1233000040147 is a deficient number, since it is larger than the sum of its proper divisors (1).

1233000040147 is an equidigital number, since it uses as much as digits as its factorization.

1233000040147 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 2016, while the sum is 25.

Adding to 1233000040147 its reverse (7410400003321), we get a palindrome (8643400043468).

The spelling of 1233000040147 in words is "one trillion, two hundred thirty-three billion, forty thousand, one hundred forty-seven".