123301402515241 has 2 divisors, whose sum is σ = 123301402515242. Its totient is φ = 123301402515240.

The previous prime is 123301402515227. The next prime is 123301402515271. The reversal of 123301402515241 is 142515204103321.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 114716502515241 + 8584900000000 = 10710579^2 + 2930000^2 .

It is a cyclic number.

It is not a de Polignac number, because 123301402515241 - 2⁴⁵ = 88117030426409 is a prime.

It is a super-3 number, since 3×123301402515241³ (a number of 43 digits) contains 333 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 123301402515197 and 123301402515206.

It is not a weakly prime, because it can be changed into another prime (123301402515271) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 61650701257620 + 61650701257621.

It is an arithmetic number, because the mean of its divisors is an integer number (61650701257621).

Almost surely, 2^{123301402515241} is an apocalyptic number.

It is an amenable number.

123301402515241 is a deficient number, since it is larger than the sum of its proper divisors (1).

123301402515241 is an equidigital number, since it uses as much as digits as its factorization.

123301402515241 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 28800, while the sum is 34.

Adding to 123301402515241 its reverse (142515204103321), we get a palindrome (265816606618562).

The spelling of 123301402515241 in words is "one hundred twenty-three trillion, three hundred one billion, four hundred two million, five hundred fifteen thousand, two hundred forty-one".