Base | Representation |
---|---|
bin | 10001111100010101011… |
… | …000010100110111010001 |
3 | 11100212121212221221121121 |
4 | 101330111120110313101 |
5 | 130200203130444101 |
6 | 2342234451522241 |
7 | 155040146504464 |
oct | 21742530246721 |
9 | 4325555857547 |
10 | 1233014312401 |
11 | 435a114866a3 |
12 | 17ab71bb9381 |
13 | 8c3713059c1 |
14 | 4396d0232db |
15 | 221182840a1 |
hex | 11f15614dd1 |
1233014312401 has 2 divisors, whose sum is σ = 1233014312402. Its totient is φ = 1233014312400.
The previous prime is 1233014312389. The next prime is 1233014312423. The reversal of 1233014312401 is 1042134103321.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 1189460709376 + 43553603025 = 1090624^2 + 208695^2 .
It is an emirp because it is prime and its reverse (1042134103321) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 1233014312401 - 27 = 1233014312273 is a prime.
It is not a weakly prime, because it can be changed into another prime (1233014312461) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 616507156200 + 616507156201.
It is an arithmetic number, because the mean of its divisors is an integer number (616507156201).
Almost surely, 21233014312401 is an apocalyptic number.
It is an amenable number.
1233014312401 is a deficient number, since it is larger than the sum of its proper divisors (1).
1233014312401 is an equidigital number, since it uses as much as digits as its factorization.
1233014312401 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1728, while the sum is 25.
Adding to 1233014312401 its reverse (1042134103321), we get a palindrome (2275148415722).
The spelling of 1233014312401 in words is "one trillion, two hundred thirty-three billion, fourteen million, three hundred twelve thousand, four hundred one".
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