Base | Representation |
---|---|
bin | 11100000010011011011000… |
… | …100110010111001001111011 |
3 | 121011121112012101221102101110 |
4 | 130002123120212113021323 |
5 | 112130321233110100011 |
6 | 1114132452315051403 |
7 | 34655002623166200 |
oct | 3402333046271173 |
9 | 534545171842343 |
10 | 123312145003131 |
11 | 36322429127857 |
12 | 119b6877a40b63 |
13 | 53a6392c8c656 |
14 | 22644a806dca7 |
15 | e3c9728bcba6 |
hex | 7026d899727b |
123312145003131 has 24 divisors (see below), whose sum is σ = 191870706751824. Its totient is φ = 70238957967360.
The previous prime is 123312145003129. The next prime is 123312145003141. The reversal of 123312145003131 is 131300541213321.
It is not a de Polignac number, because 123312145003131 - 21 = 123312145003129 is a prime.
It is a super-2 number, since 2×1233121450031312 (a number of 29 digits) contains 22 as substring.
It is not an unprimeable number, because it can be changed into a prime (123312145003141) by changing a digit.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 1339982950 + ... + 1340074971.
It is an arithmetic number, because the mean of its divisors is an integer number (7994612781326).
Almost surely, 2123312145003131 is an apocalyptic number.
123312145003131 is a deficient number, since it is larger than the sum of its proper divisors (68558561748693).
123312145003131 is a wasteful number, since it uses less digits than its factorization.
123312145003131 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2680058251 (or 2680058244 counting only the distinct ones).
The product of its (nonzero) digits is 6480, while the sum is 30.
Adding to 123312145003131 its reverse (131300541213321), we get a palindrome (254612686216452).
The spelling of 123312145003131 in words is "one hundred twenty-three trillion, three hundred twelve billion, one hundred forty-five million, three thousand, one hundred thirty-one".
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